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A G.P. consists of an even number of te...

A G.P. consists of an even number of terms. If the sum of all the terms is 5 times the sum of terms occupying odd places, then find its common ratio.

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To solve the problem, we need to find the common ratio \( r \) of a geometric progression (G.P.) with an even number of terms, given that the sum of all terms is 5 times the sum of the terms occupying odd places. ### Step-by-Step Solution: 1. **Define the Terms of the G.P.:** Let the total number of terms in the G.P. be \( 2n \) (since it is given to be even). Let the first term be \( a \) and the common ratio be \( r \). The terms of the G.P. will be: \[ a, ar, ar^2, ar^3, \ldots, ar^{2n-1} ...
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A.G.P.consists of an even number of terms.If the sum of all the terms is 5 xx the sum of the terms occupying he odd places.Find the common ratio of the G.P.

The number of terms of a G.P. are even. If the sum of all terms of the series is 5 times the sum of all terms at odd positions, then find the common ratio.

Knowledge Check

  • A.G.P. consists of an even number of terms. If the sum of all the terms is 5 times the sum of the terms occupying odd places, the common ratio will be

    A
    2
    B
    3
    C
    4
    D
    5
  • A geometric progression (GP) consists of 200 terms. If the sum of odd terms of the GP is m, and the sum of even terms of the GP is n. then what is its common ratio ?

    A
    `m//n`
    B
    `n//m`
    C
    `m+(n//m)`
    D
    `n+(m//n)`
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