Sum of the first p, q and r terms of an A.P are a, b and c, respectively.Prove that `a/p(q-r)+b/q(r-p)+c/r(p-q)=0`

Explanation

To prove the equation \( \frac{a}{p(q-r)} + \frac{b}{q(r-p)} + \frac{c}{r(p-q)} = 0 \), we start by recalling the formula for the sum of the first \( n \) terms of an arithmetic progression (A.P.).

### Step 1: Write the formula for the sum of the first \( n \) terms of an A.P.
The sum of the first \( n \) terms of an A.P. is given by:
\[ S_n = \frac{n}{2} \left(2a + (n-1)d\right) \]
where \( a \) is the first term and \( d \) is the common difference.
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