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Two faraday of electricity is passed thr...

Two faraday of electricity is passed through a solution of `CuSO_(4)`. The mass of copper deposited at the cathode is: (at mass of Cu = 63.5 amu)

A

0g

B

63.5g

C

2g

D

127g

Text Solution

Verified by Experts

The correct Answer is:
B
`underset(2F)(Cu^(2+)+2e^(-))underset("1 mole")(toCu)`
`=63.5g`
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Knowledge Check

  • Two faraday of electricity is passed through a solution of CuSO_(4) . The mass of copper deposited at the cthode is : (at mass of cu = 63.5 amu)

    A
    127 g
    B
    0 g
    C
    63.5 g
    D
    2 g

  • Two Faraday of electricity is passed through a solution of CuSO_(4) . The mass of copper deposited at the cathode is (at. Mass of Cu=63.5u)

    A
    0g
    B
    63.5g
    C
    2g
    D
    127g

  • Two faraday of electricity is passed through a solution of CuSO_(4) . The mass of Cu deposited at the cathode is (Atomic mass of Cu = 63.5 u)

    A
    0 g
    B
    63.5 g
    C
    2 g
    D
    127 g

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