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On addition of cone. H2SO4 to a chloride...

On addition of cone. `H_2SO_4` to a chloride salt, colourless fumes are evolved but in case of iodide salt, violet fumes come out. This is because ……...

A

`H_2SO_4` reduces HI to `I_2`

B

HI is of violet colour

C

HI gets oxidised to `I_(2)`

D

HI changes to `HIO_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
`H_(2)SO_(4)` oxidising HI to `I_(2)`
`2Nal + H_(2)SO_(4) to Na_(2)SO_(4) + underset(2H_(2)O + SO_(2) + I_(2))underset(darr H_(2)SO_(4))(2HI)`
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In a cell that utilises the reaction. Zn(s) +2H^(+)(aq) rarr Zn^(2+) (aq) +H_(2)(s) addition of H_(2)SO_(4) to cathode compartement, will: (1) increase the E_(Cell) and shift equilibrium to the right (2) lower the E_(cell) and shift equilibrium to the right (3) lower the E_(cell) and shift equilibrium to the left (4) increase the E_(cell) and shift equilibrium to the left

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Knowledge Check

  • Assertion : NaCl reacts with concentrated H_2SO_4 to give colourless fumes with pungent smell. But on adding MnO_(2) the fumes become greenish yellow. Reason : MnO_2 oxidises HCl to chlorine gas which is greenish yellow.

    A
    Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.
    B
    Both assertion and reason are correct statements, but reason is not the correct explanation of the assertion.
    C
    Assertion is correct, but reason is wrong statement.
    D
    Assertion is wrong but reason is correct statement.

  • Hot cone. H_2SO_4 acts as moderately strong oxidising agent. It oxidises both metals and non-metals. Which of the following element is oxidised by cone. H_2SO_4 into two gaseous products ?

    A
    Cu
    B
    S
    C
    C
    D
    Zn

  • In which of the following reactions cone. H_2SO_4 is used as an oxidising reagent ?

    A
    `CaF_(2) + H_(2)SO_(4) to CaSO_(4) + 2HF`
    B
    `2HI + H_(2)SO_(4) to I_(2) + SO_(2) + 2H_(2)O`
    C
    `Cu + 2H_(2)SO_(4) to CuSO_(4) + SO_(2) + 2H_(2)O`
    D
    `NaCl + H_(2)SO_(4) to NaHSO_(4) + HCl`

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