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If a, b and c are three integers such th...

If a, b and c are three integers such that at least two of them are unequal and `omega (ne 1)` is a cube root of unit, then the least value of the expression `|a + b omega + c omega^(2)|` is

A

0

B

1

C

`(sqrt(3))/(2)`

D

`(1)/(2)`

Text Solution

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The correct Answer is:
To find the least value of the expression \( |a + b \omega + c \omega^2| \), where \( \omega \) is a cube root of unity and at least two of the integers \( a, b, c \) are unequal, we can follow these steps: ### Step 1: Understand the properties of \( \omega \) The cube roots of unity are given by: \[ \omega = e^{2\pi i / 3} = -\frac{1}{2} + i \frac{\sqrt{3}}{2} \] and \[ \omega^2 = e^{-2\pi i / 3} = -\frac{1}{2} - i \frac{\sqrt{3}}{2} \] We also know that: \[ 1 + \omega + \omega^2 = 0 \] ### Step 2: Rewrite the expression We can express \( \omega^2 \) in terms of \( \omega \): \[ \omega^2 = -1 - \omega \] Thus, we can rewrite the expression: \[ |a + b \omega + c \omega^2| = |a + b \omega + c(-1 - \omega)| = |(a - c) + (b - c) \omega| \] ### Step 3: Identify the real and imaginary parts Let \( x = a - c \) and \( y = b - c \). Then the expression simplifies to: \[ |x + y \omega| = |x + y\left(-\frac{1}{2} + i \frac{\sqrt{3}}{2}\right)| \] This gives us: \[ |x - \frac{y}{2} + i \frac{\sqrt{3}}{2} y| \] ### Step 4: Calculate the modulus The modulus of a complex number \( z = x + iy \) is given by: \[ |z| = \sqrt{x^2 + y^2} \] Thus, we have: \[ |x - \frac{y}{2} + i \frac{\sqrt{3}}{2} y| = \sqrt{\left(x - \frac{y}{2}\right)^2 + \left(\frac{\sqrt{3}}{2} y\right)^2} \] ### Step 5: Expand and simplify Expanding this, we get: \[ = \sqrt{\left(x - \frac{y}{2}\right)^2 + \frac{3}{4} y^2} \] \[ = \sqrt{x^2 - xy + \frac{1}{4}y^2 + \frac{3}{4}y^2} \] \[ = \sqrt{x^2 - xy + y^2} \] ### Step 6: Find the minimum value To minimize \( \sqrt{x^2 - xy + y^2} \), we note that since \( a, b, c \) are integers and at least two are unequal, the minimum distance between any two integers is 1. Therefore, we can set \( |y| = 1 \) and \( |x| = 1 \), leading to: \[ x^2 - xy + y^2 \geq 1 \] The minimum value occurs when \( x = 1 \) and \( y = 1 \) or any permutation thereof, yielding: \[ \sqrt{1^2 - 1 \cdot 1 + 1^2} = \sqrt{1} = 1 \] ### Conclusion Thus, the least value of the expression \( |a + b \omega + c \omega^2| \) is: \[ \boxed{1} \]
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