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If (Kn)/( Ln)= 1024 where K(n) = int(0)^...

If `(K_n)/( L_n)= 1024` where `K_(n) = int_(0)^(1) x^(n) (2-x)^(n) dx, L_(n) = int_(0)^(1) x^(n) (1-x)^(n) dx`, then `n` is equal to

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`2.50`
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  • If int_(0)^(1) x^(m) (1-x)^(n) dx= R int_(0)^(1) x^(n) (1-x)^(m) dx , then

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    B
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    B
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    C
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    D
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