int0^sqrt2 [x^2]dx...

`int_0^sqrt2 [x^2]dx`

A

`2- sqrt2`

B

`2+ sqrt2`

C

`sqrt2-1`

D

`sqrt2-2`

Text Solution

Verified by Experts

The correct Answer is:

C

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int_0^(sqrt(2)) [x^2] dx is equal to (A) 2-sqrt(2) (B) 2+sqrt(2) (C) sqrt(2)-1 (D) sqrt(2)-2

If [dot]a n d\ {dot} denote respectively the greatest integer and fractional part functional respectively, evaluate the following integral: int_0^(sqrt(2))[x^2]dx

Knowledge Check

int_(0)^(sqrt(2)) [x^(2)]dx , is

A

`2-sqrt(2)`

B

`2+sqrt(2)`

C

`sqrt(2)-1`

D

`sqrt(2)-2`

What is int_(0)^(sqrt(2))[x^(2)] dx equal to (where [.] is the greatest integer function ) ?

A

`sqrt(2) - 1`

B

`1-sqrt(2)`

C

`2(sqrt(2) - 1)`

D

`sqrt(3) - 1`

The value of int_(0)^(sqrt(2)) [ x^(2)] dx where [*] is the greatest integer function

A

`2-sqrt(2)`

B

`2+sqrt(2)`

C

`sqrt(2)-1`

D

`sqrt(2)-1`

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