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If A and G be A.M. and GM., respectively...

If A and G be A.M. and GM., respectively between two positive numbers, prove that the numbers are `A+-sqrt((A+G)(A-G))`.

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To prove that the two positive numbers \( a \) and \( b \) can be expressed as \( A \pm \sqrt{(A + G)(A - G)} \), where \( A \) is the arithmetic mean (A.M.) and \( G \) is the geometric mean (G.M.) of \( a \) and \( b \), we will follow these steps: ### Step 1: Define A.M. and G.M. Let the two positive numbers be \( a \) and \( b \). The arithmetic mean \( A \) and geometric mean \( G \) are defined as: \[ A = \frac{a + b}{2} \] \[ ...
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Knowledge Check

  • The A.M., G.M. and H.M. between two positive numbers a and b are equal, then

    A
    a = b
    B
    ab = 1
    C
    `a gt b`
    D
    `a lt b`
  • If the A.M. and G.M. between two numbers are in the ratio m : n, then the numbers are in the ratio

    A
    `m + sqrt(n^(2) - m^(2)) : m - sqrt(n^(2) - m^(2))`
    B
    `m + sqrt(m^(2) + n^(2)) : m - sqrt(m^(2) + n^(2))`
    C
    `m + sqrt(m^(2) - n^(2)) : m - sqrt(m^(2) - n^(2))`
    D
    none of these
  • If the harmonic mean between two positive numbers is to their G.M. as 12 : 13, the numbers are in the ratio

    A
    `12 : 13`
    B
    `(1)/(12) : (1)/(13)`
    C
    `4 : 9`
    D
    `(1)/(4) : (1)/(9)`
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