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Elemantary unimolecular reactions have f...

Elemantary unimolecular reactions have first order rate laws, elementary bimolecular reactions have second order rate laws. A rate law is often derived from a proposed mechanism by imposing the state approximation or by assuming that there is a pre -equilibrium. A proposed mechanism must be consistent with the experiment rate law.
The decomposition of `O_(3)` obeys the mechanism give below
Step 1: `O_(3)hArrO_(2)+(O)` (both forward and backward reactions are fast)
Step 2: `O_(3)+(O)overset("slow")(to)O_(2)+O_(2)` (ignore) backward reaction), the rate of reaction is given by

A

`k[O_(3)]^(2)[O_(2)]`

B

`k[O_(3)]^(2)[O_(2)]^(-1)`

C

`k[O_(3)]^(2)`

D

`k[O_(2)]^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`K_(e)=[(O_(2)][O])/([O_(3)])implies[O]=(K_(e).[O_(3)])/([O_(2)]),r=K_(1)[O_(3)][O]=r=K_(1).[O_(3)].K_(C).([O_(3)])/([O_(2)]),r=K.[O_(3)]^(2)[O_(2)]^(-1)`
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Knowledge Check

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  • Elementary unimolecular reaction have first order rate laws, elementary bimolecular reaction have second order rate laws. A rate law is often derived from a proposed mechanism by imposiing the steady state approximation by assuming that there in pre equilibrium A proposal mechanism must be constat with the experimental rate law. The decomposition of O_(3) obeys the mechanism given below, Step 1: O_(3)hArrO_(2)+(O)- fast Step 2: O_(3)+(O)toO_(2)+O_(2)- slow Then find the incorrect one

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    Order of reaction =1
    B
    `r=k[O_(3)]^(2)[O_(2)]^(-1)`
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    D
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  • Elementary unimolecular reaction have first order rate laws, elementary bimolecular reaction have second order rate laws. A rate law is often derived from a proposed mechanism by imposiing the steady state approximation by assuming that there in pre equilibrium A proposal mechanism must be constant with the experimental rate law. The decomposition of O_(3) obeys the mechanism given below, Step 1: O_(3)hArrO_(2)+(O)- fast Step 2: O_(3)+(O)toO_(2)+O_(2)- slow The milk beacteria growth follows which order of reaction

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    0
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