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For a reaction the graph drawn between h...

For a reaction the graph drawn between half life period and reciprocal of initial concentration(1/a) gives a straight line with positive slope. The magnitude of the slope is 500 and iniital concentration of the reactant is 2M. If the initial rate of the reaction is represented as `x xx10^(-3)` units, then the value of x is _____________

Text Solution

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The correct Answer is:
8
`m=tan theta=1/K=500,r=K.[A]^(2)=(1/500)xx(2)^(2)=8xx10^(-3)`
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Knowledge Check

  • When initial concentration of the reactant is doubled, the half-life period of a zero order reaction

    A
    is tripled
    B
    is doubled
    C
    is halved
    D
    remains unchanged

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    A
    2
    B
    3
    C
    0
    D
    1

  • In a first - order reaction A to B, if K is the rate constant and initial concentration of the reactant is 0.5 M, then half-life is

    A
    `("In"2)/(K)`
    B
    `("In"2)/(Ksqrt(0.5))`
    C
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