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It was found that for a reaction, on cha...

It was found that for a reaction, on changin the temperature the `t_(1//2)` value get decreased. Hence it can be said that

A

`T_(2)gtT_(1)` Reaction is exothermic

B

`T_(2)gtT_(1)` Reaction is endothermic

C

`T_(2)gtT_(1)` Reaction may be endothermic or exothermic

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
(I) Endo : A+Energy `to` Product `r_(f)=K_(f)[A]^(1),(t_(1/2))=[0.693/(K_(f))]` if tem `uarr` then `r_(f)uarr, K_(f)uarr,(t_(1/2))darr`
(II) Exop `Ato` Product + Energy , `r_(f)=K_(f)[A]^(1)(t_(1/2))=(0.693/(K_(f)))` If `Tuarr,r_(f)darr,K_(f)darr,(t_(1/2))uarr`
(III) But for both Exo & Endo themr if `Tuarr` then `K_(f)uarr` & `(t_(1/2))darr`
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Explain why a. Two bodies at different temperatures T_(1) and T_(2) if brought in thermal contact do not necessarily settle to the mean temperature (T_(1) + T_(2))//2 . b. The coolant in a chemical or nuclear plant (i.e., the liquid used to prevent the different parts of a plant from getting too hot) should have high specific heat. c. Air pressure in a car tyre increases during driving. d. The climate of a harbour town is more temperate then that of a town in a desert at the same latitude.

In the above case, if their final temperatures are T_(1),T_(2) and T_(3) . Then .

Knowledge Check

  • The entropy value at temperature T is

    A
    `S = int _(o) ^(T) C _(P).dT`
    B
    `S = int _(o) ^(T) C _(P). TdT`
    C
    `S = int _(o) ^(T) (C _(P))/(T) .dT`
    D
    `S = int _(o) ^(T) C _(P). T ^(3) dT`

  • The entropy value at temperature T is

    A
    `S = int_(O)^(T) C_(p).dT`
    B
    `S =int_(O)^(T) C_(p). TdT`
    C
    `S = int_(O)^(T) (C_(p))/(T) .dT`
    D
    `S = int_(O)^(T) C_(p).T^(3)` dT`

  • The rate of a reaction doubles or decreases by half when temperature changes by

    A
    `1^(@)C`
    B
    `5^(@)C`
    C
    `10 ^(@)C`
    D
    `25^(@)C`

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