Total charge required for the oxidation ...

Total charge required for the oxidation of two moles `Mn_3O_4` into `MnO_4^(2-)` in presence of alķaline medium is `2.0 xx 10^(x)`, x is

Text Solution

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The correct Answer is:

`Mn_3O_4 overset(OH^(-))to MnO_4^(-2)`
` +(8)/(3) " "+6`
charge in oxidation state =` 6 -(8)/(3)`
For 3 Mn atoms `=3[6-(8)/(3)] = 10`
For 1 mole = 10
For 2 moles =` 2 xx 10 = 20 = 2 xx 10^(1) , x =1`

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The charge required for the oxidation of one mole of Mn_3O_4 " to " MnO_4^(2-) in alkaline medium is_____

3.34

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The charge required for the reduction of 0.4 mol of K_2Cr_2O_7 to Cr^(3+) ions is

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