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The correct Answer is:
A, B, C, D
(a) `HCl to H^(+) + Cl^(-)`
Cathode : ` 2H^(+) + 2e^(-) to H_2`
Anode " ` 2H_2O to O_2 + 4e^(-) + 4H^(+)` (b) `NaCl to Na^(+) + Cl^(-)`
Cathode : `2H_2O to O_2 + 2e^(-) + 4H^(+)`
Anode : `2H^(1) + 2e^(-) to H_2`
(c) Concentrated NaCl
Anode : `2Cl^(-) to Cl_2 + 2e^(-)`
Cathode : `2H^(+) +2e^(-) to H_2` (d)Anode : ` 2H_2O + O_2 + 2e^(-) + 4H^(+) to H_2 `
Cathode : `Ag^(+) + e^(-) to Ag `
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Knowledge Check

  • Matching the following

    A
    1-c,2-a,3-d,4-b
    B
    1-d,2-a,3-b,4-c
    C
    1-a,2-c,3-b,4-d
    D
    1-b,2-d,3-a,4-c
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