Home
Class 11
CHEMISTRY
Which of the following indicates Kinetic...

Which of the following indicates Kinetic gas equation ?
a) `PV = (3M)/(C^2) "   "` b) `PV = 1/3 mnC^2 "    "` c) `P = 1/3 dC^3 "     "` d) `KE = 3/2 RT`

A

a,c

B

b,d

C

a,b

D

b,c

Text Solution

Verified by Experts

The correct Answer is:
D

`PV = 1/3 mnc^2 implies PV = 1/3 dc^2`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • STATES OF MATTER

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE -III) (LEVEL -II ADVANCED)(STRAIGHT OBJECTIVE TYPE QUESTIONS)|8 Videos
  • STATES OF MATTER

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE -III) (LEVEL -II ADVANCED)(MORE THAN ONE CORRECT ANSWER TYPE QUESTIONS)|8 Videos
  • STATES OF MATTER

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE -II) (LEVEL -II ADVANCED)(INTEGER TYPE QUESTIONS)|4 Videos
  • SATURATED HYDROCARBONS

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|10 Videos
  • STOICHIOMETRY

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|59 Videos

Similar Questions

Explore conceptually related problems

Which of the following indicates RMS velocity of a gas? a) sqrt((2RT)/(M)) " " b) sqrt((3P)/(d)) " " c) sqrt((8RT)/(pi M)) " " d) sqrt((3RT)/(M))

Which of the following statements is/are correct about the coefficient B in the virial equation of state PV_m = RT (1 = B/(V_m) + C/(V_m^2) + .....)

Knowledge Check

  • If A, B, C are mutually exclusive and exhaustive events such that P(B) = (3)/(2)P(A) , P(C) = (1)/(3)P(B) then P(A) =

    A
    `1//3`
    B
    `1//2`
    C
    `3//4`
    D
    `1//4`
  • On the basis of the postulates of kinetic theory of gases, it is possible to derive the mathematical expression, commonly known as kinetic gas equation. PV = 1/3 m n u^3? where, P= Pressure of the gas, V a volume of the gas, m=Mass of a molecule, n = Number of molecules present in the given amount of a gas and u = root mean square speed For one mole of gas, PV = RT and n=N_A 1/3 m N_a u^2 = RT or 2/3 .1/2m N_A u^2 = N_A [1/2mN_Au^2 = KE "per mole"] ,2/3K.E. = RT implies K.E. 3/2RT Average kinetic energy per mol does not depend on the nature of the gas but depends only on temperature. This, when two gases are mixed at the same temperature, there will be no rise or decrease in temperature unless both react chemically. Average kinetic energy per molecule = ("Average K.E. per mole")/N = 3/2(RT)/(N) implies 3/2kT where k is the Boltzmann constant The average kinetic energy (in joule) of the molecules in 8g methane at 27&@C is.

    A
    `62.14 xx 10^(-22)J`
    B
    `72.68 xx 10^(-21) J`
    C
    `68.2 xx 10^(-21) J`
    D
    `62.14 xx 10^(-20)J`
  • On the basis of the postulates of kinetic theory of gases, it is possible to derive the mathematical expression, commonly known as kinetic gas equation. PV = 1/3 m n u^3? where, P= Pressure of the gas, V a volume of the gas, m=Mass of a molecule, n = Number of molecules present in the given amount of a gas and u = root mean square speed For one mole of gas, PV = RT and n=N_A 1/3 m N_a u^2 = RT or 2/3 .1/2m N_A u^2 = N_A [1/2mN_Au^2 = KE "per mole"] ,2/3K.E. = RT implies K.E. 3/2RT Average kinetic energy per mol does not depend on the nature of the gas but depends only on temperature. This, when two gases are mixed at the same temperature, there will be no rise or decrease in temperature unless both react chemically. Average kinetic energy per molecule = ("Average K.E. per mole")/N = 3/2(RT)/(N) implies 3/2kT where k is the Boltzmann constant Which of the following expressions correctly represents the relationship between the average molar kinetic energies of CO and N_2 molecules at the same temperature ?

    A
    `K.E.(CO) = KE.(N_2)`
    B
    `K.E.(CO) gt KE.(N_2)`
    C
    `K.E.(CO) lt KE.(N_2)`
    D
    cannot be predicated
  • Similar Questions

    Explore conceptually related problems

    The d.c.'s of the line joining the points A(4, 3, 1), B(-2, 1, -2) are

    Density of gas is inversely proportional to absolute temperature and directly proportional to pressure rArr d prop P/T rArr (dT)/P = constant rArr (d_(1)T_(1))/P_(1) =(d_(2)T_(2))/P_(2) Density at a particular temperature and pressure can be calculated bousing ideal gas equation PV = nRT rArr PV = ("mass")/("molar mass (M)") x RT P xx M =("mass")/("volume") xx RT rArr P xx M = d xx RT d=(PM)/(RT) The density of gas is 3.8 g L^(-1) at STP. The density at 27°C and 700 mm Hg pressure will be

    Density of gas is inversely proportional to absolute temperature and directly proportional to pressure rArr d prop P/T rArr (dT)/P = constant rArr (d_(1)T_(1))/P_(1) =(d_(2)T_(2))/P_(2) Density at a particular temperature and pressure can be calculated bousing ideal gas equation PV = nRT rArr PV = ("mass")/("molar mass (M)") x RT P xx M =("mass")/("volume") xx RT rArr P xx M = d xx RT d=(PM)/(RT) Which of the following has maximum density?

    Density of gas is inversely proportional to absolute temperature and directly proportional to pressure rArr d prop P/T rArr (dT)/P = constant rArr (d_(1)T_(1))/P_(1) =(d_(2)T_(2))/P_(2) Density at a particular temperature and pressure can be calculated bousing ideal gas equation PV = nRT rArr PV = ("mass")/("molar mass (M)") x RT P xx M =("mass")/("volume") xx RT rArr P xx M = d xx RT d=(PM)/(RT) The density of at 1 atm and 273K is

    On the basis of the postulates of kinetic theory of gases, it is possible to derive the mathematical expression, commonly known as kinetic gas equation. PV = 1/3 m n u^3? where, P= Pressure of the gas, V a volume of the gas, m=Mass of a molecule, n = Number of molecules present in the given amount of a gas and u = root mean square speed For one mole of gas, PV = RT and n=N_A 1/3 m N_a u^2 = RT or 2/3 .1/2m N_A u^2 = N_A [1/2mN_Au^2 = KE "per mole"] ,2/3K.E. = RT implies K.E. 3/2RT Average kinetic energy per mol does not depend on the nature of the gas but depends only on temperature. This, when two gases are mixed at the same temperature, there will be no rise or decrease in temperature unless both react chemically. Average kinetic energy per molecule = ("Average K.E. per mole")/N = 3/2(RT)/(N) implies 3/2kT where k is the Boltzmann constant In deriving the kinetic gas equation, the use of the root mean square speed of the molecules is done, hecause it is