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0.49("cal")/(cmxxKxxs)= . . .. (J)/(mxxK...

`0.49("cal")/(cmxxKxxs)= . . .. (J)/(mxxKxxs)`

Text Solution

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The correct Answer is:
49
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One end of a brass rod 2m long and having 1cm radius is maintained at 250^(@)C . When a steady state is reached , the rate of heat flow acrss any cross-section is 0.5 cal s^(-1) . What is the temperature of the other end K=0.26"cal" s^(-1) cm^(-1). ^(@)C^(-1) .

The temperature of a body rises by 44^(@)C when a certain amount of heat is given to it . The same heat when supplied to 22 g of ice at -8^(@)C , raises its temperature by 16^(@)C . The water eqivalent of the body is [Given : s_(water) = 1"cal"//g^(@)C & L_(t) = 80 "cal" //g, s_("ice") = 0.5"cal"//g^(@)C ]

Knowledge Check

  • 1kWh = …….. J

    A
    `36xx10^(6)`
    B
    `3.6xx10^(6)`
    C
    `3.6xx10^(7)`
    D
    `3.6xx10^(5)`

  • 1kWh = …….. J

    A
    `36xx10^(6)`
    B
    `3.6xx10^(6)`
    C
    `3.6xx10^(7)`
    D
    `3.6xx10^(5)`

  • 1 kWh = ......... J

    A
    `3.6 xx 10^6`
    B
    `3.6 xx 10^3`
    C
    `3.6 xx 10^(-6)`
    D
    `3.6 xx 10^(-3)`

    • Similar Questions

    Explore conceptually related problems

    Calculate the difference between the two principal specific heats of 1g of helium gas at S.T.P. Given atomic weight of helium = 4 and J = 4.186 J cal^(-1) and R = 8.31 J mol^(-1)K^(-1) .

    5 g of steam at 100^(@)C is mixed with 10 g of ice at 0^(@)C . Choose correct alternative /s) :- (Given s_("water") = 1"cal"//g ^(@)C, L_(F) = 80 cal//g , L_(V) = 540cal//g )

    The heat capacity of a silver coin is 1.128 "cal" .^@C^(-1) , What should be its mass in gram ? (The specific heat of silver is C=0.0564 "cal g"^(-1) .^@C^(-1) )

    A cylindrical rod having temperature T_(1) and T_(2) at its end. The rate of flow of heat is Q_(1)("Cal")/(s) If all linear dimensions are doubled keeping temperature constant, then the rate of flow of heat Q_(2) in ("Cal")/(s) will be . . . . . . . .

    hat(i). ( hat(k) xx hat(j)) + hat(j) .(hat(i) xx hat(k) ) + hat(k). ( hat(j) xx hat(i) ) + hat(i). (hat(i) xx hat(j) ) + hat(j) . ( hat(j) xx hat(k) ) =...........

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