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Calculate the change in pH of water when...

Calculate the change in pH of water when 0.01 mole of NaOH are added in 10 litre water.

Text Solution

Verified by Experts

The correct Answer is:
4
pH of water is 7
`M= ("no . of moles ")/(" sol . of solution (lit) ") =( 0.01)/(10 ) = 10 ^(_3) `
` pOH =3, pH =11 , "change in pH" = 11- 7= 4`
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