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The correct Answer is:
A-P; B-P; C-Q; D-S
` H_3 PO_4 hArr H^(+) +H_2PO_4^(-) `
`K_1=([H^(+) ]^(2))/(C) because [H^(+) ]=[H_2PO_4^(-)]`
` [H^(+) ]=sqrt(K_1.c )rArr [H_2PO_4^(-) ]= sqrt(K_1.c)`
` H_2PO_4^(-) hArr H^(+) +HPO_4^(-2)` ` K_2 = cancel ([H^(+) ][HPO_4^(-2) ])/cancel ([H_2PO_4^(-)] )therefore K_2 =[HPO_4^(_2) ]`
` HPO_4^(-2) hArr H^(+) +PO_4^(-3) `
`K_3 =([H^(+) ][PO_4^(-3)])/([HPO_4^(_2)]) therefore [PO_4^(-) ]=(K_2K_3)/(sqrt(K_1.c))`
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