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Find the precentage degree of dissociati...

Find the precentage degree of dissociation of 0.05 M `NH_3 at 25^(@) ` C in a solution of pH = 11

Text Solution

Verified by Experts

The correct Answer is:
2

` C = 0.0 5 ,pH = 11 , pOH = 3 `
`rArr [OH^(-)] =10 ^(-3) = Calpha `
` rArr alpha = (10^(-3))/(5 xx 10 ^(_2) ) = 2 xx1 0 ^(_2) =2%`
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Knowledge Check

  • The degree of dissociation of an acid HA in 0.1 M solution is 0.1%. Its dissociation constant is

    A
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    B
    `1 xx 10^(-7)`
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    D
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