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Find the precentage degree of dissociati...

Find the precentage degree of dissociation of 0.05 M `NH_3 at 25^(@) ` C in a solution of pH = 11

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The correct Answer is:
2
` C = 0.0 5 ,pH = 11 , pOH = 3 `
`rArr [OH^(-)] =10 ^(-3) = Calpha `
` rArr alpha = (10^(-3))/(5 xx 10 ^(_2) ) = 2 xx1 0 ^(_2) =2%`
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