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In the ring test of NO(3)^(-) ion, Fe^(2...

In the ring test of `NO_(3)^(-)` ion, `Fe^(2+)` ion reduces nitrate ion to nitric oxide, which combines with `Fe^(2+)` (aq) ion to form brown complex .
Write the reactions involved in the formation of brown ring.

Text Solution

AI Generated Solution

To understand the formation of the brown ring in the ring test for the nitrate ion (\(NO_3^-\)), we need to look at the reactions involved step by step. ### Step 1: Reduction of Nitrate Ion The first step involves the reduction of the nitrate ion (\(NO_3^-\)) by ferrous ion (\(Fe^{2+}\)) in an acidic medium. The reaction can be represented as follows: \[ NO_3^- + 3Fe^{2+} + 4H^+ \rightarrow NO + 3Fe^{3+} + 2H_2O \] ...
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Knowledge Check

  • A brown ring is formed in the ring test for NO_(3)^(-) ion. It is due to the formation of

    A
    `[Fe(H_(2)O)_(5)(NO)]^(2+)`
    B
    `FeSO_(4)cdot NO_(2)`
    C
    `[Fe(H_(2)O)_(4)(NO)_(2)]^(2+)`
    D
    `FeSO_(4)cdot HNO_(3)`
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