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If the point P(2,1)lies on the line segm...

If the point P(2,1)lies on the line segment joining points A(4,2)and B(8,4), then

A

AP `=(1)/(3)AB`

B

`AP=PB`

C

PB `=(1)/(3)AB`

D

`AP=(1)/(2)AB`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the relationship between the distances AP, PB, and AB where P(2,1) lies on the line segment joining points A(4,2) and B(8,4). ### Step-by-Step Solution: 1. **Identify the Points:** - Point A = (4, 2) - Point B = (8, 4) - Point P = (2, 1) 2. **Use the Distance Formula:** The distance formula between two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] 3. **Calculate Distance AP:** - For points A(4, 2) and P(2, 1): \[ AP = \sqrt{(2 - 4)^2 + (1 - 2)^2} = \sqrt{(-2)^2 + (-1)^2} = \sqrt{4 + 1} = \sqrt{5} \] 4. **Calculate Distance PB:** - For points P(2, 1) and B(8, 4): \[ PB = \sqrt{(8 - 2)^2 + (4 - 1)^2} = \sqrt{(6)^2 + (3)^2} = \sqrt{36 + 9} = \sqrt{45} = 3\sqrt{5} \] 5. **Calculate Distance AB:** - For points A(4, 2) and B(8, 4): \[ AB = \sqrt{(8 - 4)^2 + (4 - 2)^2} = \sqrt{(4)^2 + (2)^2} = \sqrt{16 + 4} = \sqrt{20} = 2\sqrt{5} \] 6. **Establish Relationships:** - We found: - \( AP = \sqrt{5} \) - \( PB = 3\sqrt{5} \) - \( AB = 2\sqrt{5} \) - Now, we can express the relationships: - \( AP + PB = AB \) - \( \sqrt{5} + 3\sqrt{5} = 4\sqrt{5} \) (which is not equal to \( 2\sqrt{5} \)) - However, we can find that \( PB = 3 \times AP \) and \( AB = 2 \times AP \). 7. **Final Conclusion:** - Since \( AP = \frac{1}{2} AB \), we can conclude that the correct relationship is: - \( AP = \frac{1}{2} AB \) ### Answer: The correct option is that \( AP = \frac{1}{2} AB \).

To solve the problem, we need to determine the relationship between the distances AP, PB, and AB where P(2,1) lies on the line segment joining points A(4,2) and B(8,4). ### Step-by-Step Solution: 1. **Identify the Points:** - Point A = (4, 2) - Point B = (8, 4) - Point P = (2, 1) ...
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Knowledge Check

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