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The ground state energy of hydrogen atom...

The ground state energy of hydrogen atom is `-13.6eV`. If an electron makes a transition form an energy level `-0.85 eV` to `-3.4 eV`, calculate the wavelength of spectral line emitted. To which series of hydrogen spectrum does this wavelength belongs?

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To solve the problem, we need to calculate the wavelength of the spectral line emitted when an electron transitions from an energy level of -0.85 eV to -3.4 eV in a hydrogen atom. We will also determine which series of the hydrogen spectrum this wavelength belongs to. ### Step-by-Step Solution: 1. **Identify the Energy Levels**: - The ground state energy of hydrogen is given as \( E_1 = -13.6 \, \text{eV} \). - The energy levels can be calculated using the formula: \[ ...
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The ground state energy of hydrogen atom is -13.6eV. If an electron makes a transition from an energy level -0.85 eV to -1.51 eV, calculate the wavelength of spectral line emitted. To which series of hydrogen spectrum does this wavelength belongs?

The grond state energy of hydrogen atom is 13.6 eV . If an electron makes a transition from an energy level - 1.51 eV to - 3.4 e V , calculate the wevelength of the spectrel line emitted and name the series of hydrogen spectrum to which it belongs.

Knowledge Check

  • The ground state energy of hydrogen atom is -13.6eV. What is the K.E. of electron in this state?

    A
    `2.18xx10^(-14)J`
    B
    `2.18xx10^(-16)J`
    C
    `2.18xx10^(-18)J`
    D
    `2.18xx10^(-19)J`
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