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Radiation of frequency 10^(15)Hz is inc...

Radiation of frequency `10^(15)Hz` is incident on two photosensitive surface `P` and `Q`. There is no photoemission from surface `P`. Photoemission occurs from `Q` but photoelectrons have zero kinetic energy. Explain these observation and find the value of work function for surface `Q`.

Text Solution

AI Generated Solution

To solve the problem, we need to analyze the observations regarding the two photosensitive surfaces, P and Q, when radiation of frequency \(10^{15} \text{ Hz}\) is incident on them. ### Step-by-Step Solution: 1. **Understanding Photoelectric Effect**: The photoelectric effect states that when light of sufficient frequency strikes a photosensitive material, it can eject electrons from that material. The energy of the incident photons is given by the equation: \[ E = h \nu ...
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Fig. shows the variation of stopping potential V_0 with the frequency v of the incident radiation for two photosensitive metal P and Q: (i) Explain which metal has smaller threshold wavelength (ii) Explain, giving reason, which metal emits photoelectrons having smaller kinetic energy, for the same wavelength of incident radiation. (iii) If the distance between the light source and metal P is doubled, how will the stopping potential change.

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Knowledge Check

  • When the photons of energy hv fall on a photosensitive metallic surface of work function hv_(0) , electrons are emitted are from the surface. The most energetic electron coming out of the surfece have kinetic energy equal to

    A
    hv
    B
    `hv_(0)`
    C
    `hv+hv_(0)`
    D
    `hv-hv_(0)`

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    When light of sufficiently high frequency is incident on a metallic surface, electrons are emitted from the metallic surface. This phenomenon is called photoelectric emission. Kinetic energy of the emitted photoelectrons depends on the wavelength of incident light and is independent of the intensity of light. Number of emitted photoelectrons depends on intensity. (hv-phi) is the maximum kinetic energy of emitted photoelectron (where phi is the work function of metallic surface). Reverse effect of photo emission produces X-ray. X-ray is not deflected by electric and magnetic fields. Wavelength of a continuous X-ray depends on potential difference across the tuve. Wavelength of charasteristic X-ray depends on the atomic number. Q. If potential difference across the tube is increased then

    Radiation of wavelength 310 nm is incidenton a metal surface of work function 1eV . Find maximum speed of photoelectrons emitted . ( Closed value )

    Radiation of wavelength 310 nm is incidenton a metal surface of work function 1eV . Find maximum speed of photoelectrons emitted . ( Closed value )

    When light of sufficiently high frequency is incident on a metallic surface, electrons are emitted from the metallic surface. This phenomenon is called photoelectric emission. Kinetic energy of the emitted photoelectrons depends on the wavelength of incident light and is independent of the intensity of light. Number of emitted photoelectrons depends on intensity. (hv-phi) is the maximum kinetic energy of emitted photoelectron (where phi is the work function of metallic surface). Reverse effect of photo emission produces X-ray. X-ray is not deflected by electric and magnetic fields. Wavelength of a continuous X-ray depends on potential difference across the tuve. Wavelength of charasteristic X-ray depends on the atomic number. Q. If frequency (upsilongtupsilon_0) of incident light becomes n times the initial frequency (v), then KE of the emitted photoelectrons becomes ( v_0 threshold frequency).

    The kinetic energy of photoelectrons emitted by a photosensitive surface depends on the internsity of the incident radiation

    The peak emission from a black body at a certain temprature occurs at a wavelength of 9000 Å . On increase its temperature , the total radiation emmited is increased its 81 times. At the intial temperature when the peak radiation from the black body is incident on a metal surface , it does not cause any photoemission from the surface . After the increase of temperature, the peak from the black body caused photoemission. To bring these photoelectrons to rest , a potential equivalent to the excitation energy between n = 2 and n = 3 bohr levels of hydrogen atoms is required. Find the work function of the metal.

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