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If the pair of lines a x^2+2h x y+b y^2+...

If the pair of lines `a x^2+2h x y+b y^2+2gx+2fy+c=0` intersect on the y-axis, then prove that `2fgh=bg^2+c h^2`

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To prove that if the pair of lines \( ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0 \) intersect on the y-axis, then \( 2fgh = bg^2 + ch^2 \), we can follow these steps: ### Step 1: Understand the Condition for Intersection on the Y-Axis If the lines intersect on the y-axis, it implies that at the point of intersection, the x-coordinate is 0. Therefore, we can substitute \( x = 0 \) into the given equation. ### Step 2: Substitute \( x = 0 \) into the Equation Substituting \( x = 0 \) in the equation \( ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0 \) gives: \[ ...
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Knowledge Check

  • The circle x^(2) + y^(2) + 2g x + 2fy + c = 0 does not intersect the y-axis if

    A
    A. `g^(2) lt c`
    B
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    C
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    D
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