Find the coordinates of points where pair of lines given by equation `2x^(2)-6y^(2)+xy-2x+17y-12=0` intersect line `x=1`.

Explanation

To find the coordinates of the points where the pair of lines given by the equation \(2x^2 - 6y^2 + xy - 2x + 17y - 12 = 0\) intersects the line \(x = 1\), we can follow these steps:

### Step 1: Substitute \(x = 1\) into the equation
We start by substituting \(x = 1\) into the given equation:

\[ 2(1)^2 - 6y^2 + (1)y - 2(1) + 17y - 12 = 0 \]
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