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If P is a point (x ,y) on the line y=-3x...

If `P` is a point `(x ,y)` on the line `y=-3x` such that `P` and the point (3, 4) are on the opposite sides of the line `3x-4y=8,` then `x >8/(15)` (b) `x >8/5` `y<-8/5` (d) `y<-8/(15)`

A

`x gt 8//15`

B

`x gt 8//5`

C

`x lt -8//5`

D

`y lt -8//15`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to analyze the given conditions and derive the inequalities for \( x \) and \( y \). ### Step 1: Understand the given lines and points We have: 1. The line \( y = -3x \) which represents the point \( P(x, y) \). 2. The line \( 3x - 4y = 8 \) which separates the points. 3. The point \( Q(3, 4) \). ### Step 2: Rewrite the line equation We can rewrite the line \( 3x - 4y = 8 \) in the form: \[ 3x - 4y - 8 = 0 \] This will help us evaluate whether points are on opposite sides of the line. ### Step 3: Evaluate the position of point \( Q(3, 4) \) Substituting \( Q(3, 4) \) into the line equation: \[ 3(3) - 4(4) - 8 = 9 - 16 - 8 = -15 \] Since the result is negative, point \( Q \) lies on one side of the line. ### Step 4: Determine the condition for point \( P(x, y) \) For point \( P(x, y) \) to be on the opposite side of the line, we need: \[ 3x - 4y - 8 > 0 \] ### Step 5: Substitute \( y \) from the line equation Since \( P \) lies on the line \( y = -3x \), we substitute \( y \): \[ 3x - 4(-3x) - 8 > 0 \] This simplifies to: \[ 3x + 12x - 8 > 0 \] \[ 15x - 8 > 0 \] ### Step 6: Solve for \( x \) Rearranging gives: \[ 15x > 8 \implies x > \frac{8}{15} \] ### Step 7: Determine the condition for \( y \) Next, we need to find the condition for \( y \). Substitute \( y = -3x \) into the inequality: \[ 3x - 4(-3x) - 8 > 0 \] This leads to: \[ 3x + 12x - 8 > 0 \implies 15x - 8 > 0 \] Now substituting \( y \): \[ 3x - 4y - 8 > 0 \implies 3x - 4(-3x) - 8 > 0 \] This simplifies to: \[ 3x + 12x - 8 > 0 \] \[ 15x - 8 > 0 \implies x > \frac{8}{15} \] Now substituting \( x = -\frac{y}{3} \) into the inequality: \[ 3(-\frac{y}{3}) - 4y - 8 > 0 \] This simplifies to: \[ -y - 4y - 8 > 0 \implies -5y - 8 > 0 \implies 5y < -8 \implies y < -\frac{8}{5} \] ### Conclusion Thus, we have derived: 1. \( x > \frac{8}{15} \) 2. \( y < -\frac{8}{5} \) ### Final Answer The correct options are: (a) \( x > \frac{8}{15} \) and (c) \( y < -\frac{8}{5} \).

To solve the problem step by step, we need to analyze the given conditions and derive the inequalities for \( x \) and \( y \). ### Step 1: Understand the given lines and points We have: 1. The line \( y = -3x \) which represents the point \( P(x, y) \). 2. The line \( 3x - 4y = 8 \) which separates the points. 3. The point \( Q(3, 4) \). ...
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