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A B C is an isosceles triangle. If the c...

`A B C` is an isosceles triangle. If the coordinates of the base are `B(1,3)` and `C(-2,7)` , the coordinates of vertex `A`

A

(1,6)

B

`(-1//2,5) `

C

`(-5//6,6) `

D

none of these

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To find the coordinates of vertex A in the isosceles triangle ABC with base BC, we will follow these steps: ### Step 1: Identify the coordinates of points B and C The coordinates of point B are \( B(1, 3) \) and the coordinates of point C are \( C(-2, 7) \). ### Step 2: Set up the coordinates for point A Let the coordinates of point A be \( A(x, y) \). ### Step 3: Use the distance formula Since triangle ABC is isosceles, we know that the lengths of sides AB and AC are equal. We will use the distance formula to express this condition: \[ AB = AC \] Using the distance formula, we can express the lengths as follows: \[ AB = \sqrt{(x - 1)^2 + (y - 3)^2} \] \[ AC = \sqrt{(x + 2)^2 + (y - 7)^2} \] ### Step 4: Set the lengths equal and square both sides Setting the lengths equal gives us: \[ \sqrt{(x - 1)^2 + (y - 3)^2} = \sqrt{(x + 2)^2 + (y - 7)^2} \] Squaring both sides removes the square roots: \[ (x - 1)^2 + (y - 3)^2 = (x + 2)^2 + (y - 7)^2 \] ### Step 5: Expand both sides Expanding both sides results in: \[ (x^2 - 2x + 1) + (y^2 - 6y + 9) = (x^2 + 4x + 4) + (y^2 - 14y + 49) \] ### Step 6: Simplify the equation Cancelling \( x^2 \) and \( y^2 \) from both sides gives: \[ -2x + 10 = 4x + 53 - 14y \] Rearranging terms leads to: \[ -2x - 4x + 14y + 10 - 53 = 0 \] This simplifies to: \[ -6x + 14y - 43 = 0 \] ### Step 7: Rearranging the equation We can rearrange this to: \[ 6x - 14y + 43 = 0 \] ### Step 8: Check the options Now, we will check which of the given options satisfies this equation: 1. **Option 1: \( (1, 6) \)** \[ 6(1) - 14(6) + 43 = 6 - 84 + 43 = -35 \quad (\text{not valid}) \] 2. **Option 2: \( \left(-\frac{1}{2}, 5\right) \)** \[ 6\left(-\frac{1}{2}\right) - 14(5) + 43 = -3 - 70 + 43 = -30 \quad (\text{not valid}) \] 3. **Option 3: \( \left(-\frac{5}{6}, 6\right) \)** \[ 6\left(-\frac{5}{6}\right) - 14(6) + 43 = -5 - 84 + 43 = -46 \quad (\text{not valid}) \] 4. **Option 4: None of these** Since none of the options satisfy the equation, the answer is: ### Final Answer The coordinates of vertex A do not match any of the options provided. ---

To find the coordinates of vertex A in the isosceles triangle ABC with base BC, we will follow these steps: ### Step 1: Identify the coordinates of points B and C The coordinates of point B are \( B(1, 3) \) and the coordinates of point C are \( C(-2, 7) \). ### Step 2: Set up the coordinates for point A Let the coordinates of point A be \( A(x, y) \). ...
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CENGAGE ENGLISH-COORDINATE SYSYEM -Exercises
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  2. If two vertices of a triangle are (1,3) and (4,-1) and the area of tri...

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  3. Which of the following sets of points form an equilateral triangle? (...

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  4. A particle p moves from the point A(0,4) to the point 10 ,-4) . The pa...

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  5. If |x1y1 1x2y2 1x3y3 1|=|a1b1 1a2b2 1a3b3 1| then the two triangles ...

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  6. O P Q R is a square and M ,N are the middle points of the sides P Qa n...

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  7. A straight line passing through P(3,1) meets the coordinate axes at Aa...

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  8. Let A-=(3,-4),B-=(1,2)dot Let P-=(2k-1,2k+1) be a variable point such ...

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  9. The polar coordinates equivalent to (-3,sqrt3) are

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  11. P and Q are points on the line joining A(-2,5) and B(3,1) such that A ...

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  12. In triangle ABC, angle B is right angled, AC=2 and A(2,2), B(1,3) then...

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  13. One vertex of an equilateral triangle is (2,2) and its centroid is (-2...

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  14. ABCD is a rectangle with A(-1,2),B(3,7) and AB:BC=4:3. If P is the cen...

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  15. If (2,-3), (6,-5) and (-2,1) are three consecutive verticies of a rohm...

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  16. If poitns A(3,5) and B are equidistant from H(sqrt2,sqrt5) and B has r...

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  17. Le n be the number of points having rational coordinates equidistant ...

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  18. In a triangle ABC the sides BC=5, CA=4 and AB=3. If A(0,0) and the int...

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  19. If A(0, 0), B(1, 0) and C(1/2,sqrt(3)/2) then the centre of the circle...

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  20. Statement 1: If in a triangle, orthocentre, circumcentre and centroid ...

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