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If the circle x^2+y^2-4x-8y-5=0 intersec...

If the circle `x^2+y^2-4x-8y-5=0` intersects the line `3x-4y=m` at two distinct points, then find the values of `mdot`

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To solve the problem, we need to find the values of \( m \) such that the line \( 3x - 4y = m \) intersects the circle given by the equation \( x^2 + y^2 - 4x - 8y - 5 = 0 \) at two distinct points. ### Step 1: Rewrite the equation of the circle The given equation of the circle is: \[ x^2 + y^2 - 4x - 8y - 5 = 0 \] We can rewrite it in standard form by completing the square. ### Step 2: Complete the square 1. For \( x^2 - 4x \): \[ x^2 - 4x = (x - 2)^2 - 4 \] 2. For \( y^2 - 8y \): \[ y^2 - 8y = (y - 4)^2 - 16 \] Now, substituting back into the equation: \[ (x - 2)^2 - 4 + (y - 4)^2 - 16 - 5 = 0 \] This simplifies to: \[ (x - 2)^2 + (y - 4)^2 - 25 = 0 \] Thus, the equation of the circle in standard form is: \[ (x - 2)^2 + (y - 4)^2 = 25 \] This indicates that the center of the circle is \( (2, 4) \) and the radius \( r = 5 \). ### Step 3: Find the distance from the center to the line The line can be rewritten as: \[ 3x - 4y - m = 0 \] To find the distance \( d \) from the center \( (2, 4) \) to the line, we use the formula: \[ d = \frac{|Ax_1 + By_1 + C|}{\sqrt{A^2 + B^2}} \] where \( A = 3 \), \( B = -4 \), \( C = -m \), and \( (x_1, y_1) = (2, 4) \). Substituting these values: \[ d = \frac{|3(2) - 4(4) - m|}{\sqrt{3^2 + (-4)^2}} = \frac{|6 - 16 - m|}{\sqrt{9 + 16}} = \frac{| -10 - m|}{5} \] ### Step 4: Set the condition for two distinct intersections For the line to intersect the circle at two distinct points, the distance \( d \) must be less than the radius \( r \): \[ \frac{| -10 - m|}{5} < 5 \] Multiplying both sides by 5: \[ | -10 - m| < 25 \] ### Step 5: Solve the inequality This absolute value inequality can be split into two inequalities: 1. \( -10 - m < 25 \) 2. \( -10 - m > -25 \) Solving the first inequality: \[ -10 - m < 25 \implies -m < 35 \implies m > -35 \] Solving the second inequality: \[ -10 - m > -25 \implies -m > -15 \implies m < 15 \] ### Step 6: Combine the results Thus, the values of \( m \) for which the line intersects the circle at two distinct points are: \[ -35 < m < 15 \] ### Final Answer The values of \( m \) are: \[ m \in (-35, 15) \]

To solve the problem, we need to find the values of \( m \) such that the line \( 3x - 4y = m \) intersects the circle given by the equation \( x^2 + y^2 - 4x - 8y - 5 = 0 \) at two distinct points. ### Step 1: Rewrite the equation of the circle The given equation of the circle is: \[ x^2 + y^2 - 4x - 8y - 5 = 0 \] We can rewrite it in standard form by completing the square. ...
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