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In triangle ABC, if cosA+sinA-(2)/(cosB+...

In `triangle ABC`, if `cosA+sinA-(2)/(cosB+sinB)=0` then prove that triangle is isosceles right angled.

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To prove that triangle ABC is isosceles right-angled given the equation \( \cos A + \sin A - \frac{2}{\cos B + \sin B} = 0 \), we can follow these steps: ### Step 1: Rewrite the given equation Starting from the given equation: \[ \cos A + \sin A - \frac{2}{\cos B + \sin B} = 0 \] We can rearrange this to: ...
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