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Let the terms a(1),a(2),a(3),…a(n) be in...

Let the terms `a_(1),a_(2),a_(3),…a_(n)` be in G.P. with common ratio r. Let `S_(k)` denote the sum of first k terms of this G.P.. Prove that `S_(m-1)xxS_(m)=(r+1)/r`SigmaSigma_(i le itj le n)a_(i)a_(j)`

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To prove that \( S_{m-1} \times S_m = \frac{r + 1}{r} \sum_{1 \leq i < j \leq n} a_i a_j \), we will follow these steps: ### Step 1: Define the terms of the G.P. Let the first term of the G.P. be \( a_1 \) and the common ratio be \( r \). The terms can be expressed as: \[ a_k = a_1 r^{k-1} \quad \text{for } k = 1, 2, \ldots, n \] ...
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Knowledge Check

  • The sum of terms of a G.P if a_(1)=3,a_(n)=96 and S_(n)=189 is

    A
    5
    B
    6
    C
    7
    D
    8
  • If the first term of a G.P. a_(1),a_(2),a_(3) is unity such that 4a_(2)+5a_(3) is least, then the common ratio of the G.P. is

    A
    `2/5`
    B
    `-2/5`
    C
    `-3/5`
    D
    `-1/5`
  • If a_(1)=3 and a_(n)=n+a_(n-1) , the sum of the first five term is

    A
    17
    B
    30
    C
    42
    D
    45
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