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Find the least value of `secA+secB+secC` in an acute angled triangle.

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Triangle ABC is acute angled
`therefore 0 ltA,B,C lt pi//2`
so , consdier the graph of function `y = sec x for x in (0,pi//2)`
The graph of funtion is concave upward
`therefore (secA+secB+secC)/(3)gesec(A+B+C)/(3)`
`rarr (secA+secB+secC)/(3)gesec(pi)/(3)`
`rarr secA+secB+secCge6`
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CENGAGE ENGLISH-MONOTONICITY AND MAXIMA MINIMA OF FUNCTIONS-Concept Application Exercise 6.4
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