• NEET
      • Class 11th
      • Class 12th
      • Class 12th Plus
    • JEE
      • Class 11th
      • Class 12th
      • Class 12th Plus
    • Class 6-10
      • Class 6th
      • Class 7th
      • Class 8th
      • Class 9th
      • Class 10th
    • View All Options
      • Online Courses
      • Distance Learning
      • Hindi Medium Courses
      • International Olympiad
    • NEET
      • Class 11th
      • Class 12th
      • Class 12th Plus
    • JEE (Main+Advanced)
      • Class 11th
      • Class 12th
      • Class 12th Plus
    • JEE Main
      • Class 11th
      • Class 12th
      • Class 12th Plus
  • Classroom
    • NEET
      • 2025
      • 2024
      • 2023
      • 2022
    • JEE
      • 2025
      • 2024
      • 2023
      • 2022
    • Class 6-10
    • JEE Main
      • Previous Year Papers
      • Sample Papers
      • Result
      • Analysis
      • Syllabus
      • Exam Date
    • JEE Advanced
      • Previous Year Papers
      • Sample Papers
      • Mock Test
      • Result
      • Analysis
      • Syllabus
      • Exam Date
    • NEET
      • Previous Year Papers
      • Sample Papers
      • Mock Test
      • Result
      • Analysis
      • Syllabus
      • Exam Date
      • College Predictor
      • Counselling
    • NCERT Solutions
      • Class 6
      • Class 7
      • Class 8
      • Class 9
      • Class 10
      • Class 11
      • Class 12
    • CBSE
      • Notes
      • Sample Papers
      • Question Papers
    • Olympiad
      • NSO
      • IMO
      • NMTC
  • NEW
    • TALLENTEX
    • AOSAT
  • ALLEN E-Store
    • ALLEN for Schools
    • About ALLEN
    • Blogs
    • News
    • Careers
    • Request a call back
    • Book home demo
Home
Class 12
MATHS
If 2a+3b+6c = 0, then show that the equa...

If 2a+3b+6c = 0, then show that the equation `a x^2 + bx + c = 0` has atleast one real root between 0 to 1.

To view this video, please enable JavaScript and consider upgrading to a web browser thatsupports HTML5 video

Text Solution

AI Generated Solution

Doubtnut Promotions Banner Desktop LightDoubtnut Promotions Banner Desktop DarkDoubtnut Promotions Banner Mobile LightDoubtnut Promotions Banner Mobile Dark

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    CENGAGE ENGLISH|Exercise SOLVED EXAMPLES|15 Videos
  • APPLICATION OF DERIVATIVES

    CENGAGE ENGLISH|Exercise MATRIX MATCH TYPE|3 Videos
  • APPLICATION OF DERIVATIVES

    CENGAGE ENGLISH|Exercise JEE PREVIOUS YEAR|10 Videos
  • 3D COORDINATION SYSTEM

    CENGAGE ENGLISH|Exercise DPP 3.1|11 Videos
  • APPLICATION OF INTEGRALS

    CENGAGE ENGLISH|Exercise All Questions|142 Videos

Similar Questions

Explore conceptually related problems

Statement-1: If a, b, c in R and 2a + 3b + 6c = 0 , then the equation ax^(2) + bx + c = 0 has at least one real root in (0, 1). Statement-2: If f(x) is a polynomial which assumes both positive and negative values, then it has at least one real root.

If 27a+9b+3c+d=0 then the equation 4ax^(3)+3bx^(2)+2cx+d has at leat one real root lying between

If the equation ax^(2) + bx + c = 0, a,b, c, in R have non -real roots, then

If 4a+2b+c=0 , then the equation 3ax^(2)+2bx+c=0 has at least one real lying in the interval

Let a , b , c be nonzero real numbers such that int_0^1(1+cos^8x)(a x^2+b x+c)dx =int_0^2(1+cos^8x)(a x^2+b x+c)dx=0 Then show that the equation a x^2+b x+c=0 will have one root between 0 and 1 and other root between 1 and 2.

Let a , b , c be nonzero real numbers such that int_0^1(1+cos^8x)(a x^2+b x+c)dx =int_0^2(1+cos^8x)(a x^2+b x+c)dx=0 Then show that the equation a x^2+b x+c=0 will have one root between 0 and 1 and other root between 1 and 2.

If a, b, c ∈ R, a ≠ 0 and the quadratic equation ax^2 + bx + c = 0 has no real root, then show that (a + b + c) c > 0

If a, b, c, d are real numbers such that (a+2c)/(b+3d)+(4)/(3)=0 . Prove that the equation ax^(3)+bx^(2)+cx+d=0 has atleast one real root in (0, 1).

If the equation a x^2+b x+c=0 has two positive and real roots, then prove that the equation a x^2+(b+6a)x+(c+3b)=0 has at least one positive real root.

If a, b, c in R and the quadratic equation x^2 + (a + b) x + c = 0 has no real roots then

CENGAGE ENGLISH-APPLICATION OF DERIVATIVES-ILLUSTRATION
  1. Find the approximate value of f(5. 001), where f(x)=x^3-7x^2+15.

    04:54

    |

  2. Find the approximate change in the volume V of a cube of side x meters...

    02:02

    |

  3. Discuss the applicability of Rolles theorem for the following funct...

    05:26

    |

  4. If the function f(x)=x^3-6x^2+a x+b defined on [1,3] satisfies Rolles ...

    05:40

    |

  5. Show that between any two roots of e^(-x)-cosx=0, there exists at leas...

    03:25

    |

  6. How many roots of the equation (x-1)(x-2)(x-3) + (x-1)(x-2)(x-4) + (x-...

    03:48

    |

  7. If 2a+3b+6c = 0, then show that the equation a x^2 + bx + c = 0 has at...

    04:09

    |

  8. Let f(x) be differentiable function and g(x) be twice differentiable f...

    05:42

    |

  9. Let f(x) be differentiable function and g(x) be twice differentiable f...

    05:42

    |

  10. Let P(x) be a polynomial with real coefficients, Let a , b in R ,a < ...

    04:07

    |

  11. The fucntion f(x)=x^(3)-6ax^(2)+5x satisfies the conditions of Lagrang...

    06:53

    |

  12. If f : [ 5, 5] Ris a differentiable function and if f^(prime)(x)does ...

    03:15

    |

  13. Let f be differentiable for all x , If f(1)=-2a n df^(prime)(x)geq2 fo...

    02:33

    |

  14. Let f:[2,7]vec[0,oo) be a continuous and differentiable function. Then...

    03:59

    |

  15. Let f(x)a n dg(x) be differentiable function in (a , b), continuous at...

    05:06

    |

  16. Using Lagranges mean value theorem, prove that |cosa-cosb|<|a-b|dot

    02:53

    |

  17. Using lagrange's mean value theorem, show that (beta-alpha)/(1+beta^2...

    03:42

    |

  18. Prove that 1/28 lt (28) ^(1//3)-3lt 1/27

    01:39

    |

  19. Let f(x)a n dg(x) be two differentiable functions in Ra n df(2)=8,g(2)...

    02:25

    |

  20. Let f be continuous on [a , b],a >0,a n d differentiable on (a , b)dot...

    04:20

    |

Home
Profile
|