The surface tension of water is 72 dyne//cm. convert it inSI unit.

Explanation

To convert the surface tension of water from CGS units (dyne/cm) to SI units (Newton/m), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given surface tension**:
We have the surface tension \( T = 72 \, \text{dyne/cm} \).

2. **Understand the conversion factors**:
- 1 dyne = \( 10^{-5} \) Newton
- 1 cm = \( 10^{-2} \) meters

3. **Convert dyne to Newton**:
To convert the dyne part of the surface tension to Newtons, we multiply by the conversion factor:
\[ 72 \, \text{dyne} = 72 \times 10^{-5} \, \text{N} \]

4. **Convert cm to meters**:
To convert the centimeter part of the surface tension to meters, we convert the denominator:
\[ 1 \, \text{cm} = 10^{-2} \, \text{m} \]

5. **Combine the conversions**:
Now we can express the surface tension in SI units:
\[ T = \frac{72 \times 10^{-5} \, \text{N}}{10^{-2} \, \text{m}} \]

6. **Simplify the expression**:
When we simplify the above expression:
\[ T = 72 \times 10^{-5} \times 10^{2} \, \text{N/m} = 72 \times 10^{-3} \, \text{N/m} \]

7. **Final answer**:
Thus, the surface tension in SI units is:
\[ T = 0.072 \, \text{N/m} \]