The metre is defined as the distance travelled by ligh in `(1)/(299,792,458)` second. Why didn't people choose some easier number such as `(1)/(300.000.000)` second?

A freely falling body traveled xm in n^(th) second distance travelled in n-1^(th) second is

The speed of a car increases uniformly from zero to 10ms^-1 in 2s and then remains constant (figure) a. Find the distance travelled by the car in the first two seconds. b. Find the distance travelled by the car in the next two seconds. c. Find the total distance travelled in 4s .

A particle is moving in a straight line with initial velocity u and uniform acceleration f . If the sum of the distances travelled in t^(th) and (t + 1)^(th) seconds is 100 cm , then its velocity after t seconds, in cm//s , is.

A car travels 25 m in 1 second. How much distance will it cover in 2 minutes ?

A body is thrown up with a velocity 29.23 "ms"^(-1) distance travelled in last second of upward motion is

The distance travelled by a particle in n^(th) second is S_n =u+a/2 (2n-1) where u is the velocity and a is the acceleration. The equation is

Assertion : In the equation, s=u+at-(1)/(2)a where, s is the distance travelled by uniformly accelerated body in tth second. Reason : The above equation is dimensionally incorrect.

A body is projected with a velocity 50 "ms"^(-1) . Distance travelled in 6th second is [g=10 ms^(-2)]

Consider a particle intially moving with a velocity of 5 m s^(-1) starts decelerating at a constant rate of 2 m s^(-2) . a. Determine the time at which the particle becomes stationary. b. Find the distance travelled in the second second. c. Find the distance travelled in the third second.

A body is projected with a velocity 60 ms^(-1) vertically upwards the distance travelled in last second of its motion is [g=10 ms^(-1)]