The oxidation number of sulphur in `S_(8),S_(2)F_(2),H_(2)S and H_(2)SO_(4)` respectively are:

Options

A. `0, +1, -2 and 6`
B. `+2,0, +2 and 6`
C. `0, +1, +2 and 6`
D. ` -2,0, +2 and 6`

Answer

To find the oxidation number of sulfur in the compounds \( S_8, S_2F_2, H_2S, \) and \( H_2SO_4 \), we will analyze each compound step by step.

### Step 1: Determine the oxidation number of sulfur in \( S_8 \)

- **Explanation**: In its elemental form, the oxidation number of any element is always 0. Since \( S_8 \) is a molecule made entirely of sulfur atoms, the oxidation number of sulfur in \( S_8 \) is 0.

**Oxidation number of sulfur in \( S_8 \) = 0**

### Step 2: Determine the oxidation number of sulfur in \( S_2F_2 \)

- **Explanation**: In \( S_2F_2 \), we need to consider the oxidation states of fluorine, which is -1. Let the oxidation number of sulfur be \( x \). The equation can be set up as follows:

\[ 2x + 2(-1) = 0 \]

Simplifying this gives:

\[ 2x - 2 = 0 \implies 2x = 2 \implies x = +1 \]

**Oxidation number of sulfur in \( S_2F_2 \) = +1**

### Step 3: Determine the oxidation number of sulfur in \( H_2S \)

- **Explanation**: In \( H_2S \), the hydrogen atoms have an oxidation number of +1. Let the oxidation number of sulfur be \( x \). The equation can be set up as follows:

\[ 2(+1) + x = 0 \]

Simplifying this gives:

\[ 2 + x = 0 \implies x = -2 \]

**Oxidation number of sulfur in \( H_2S \) = -2**

### Step 4: Determine the oxidation number of sulfur in \( H_2SO_4 \)

- **Explanation**: In \( H_2SO_4 \), the hydrogen atoms have an oxidation number of +1 and the oxygen atoms have an oxidation number of -2. Let the oxidation number of sulfur be \( x \). The equation can be set up as follows:

\[ 2(+1) + x + 4(-2) = 0 \]

Simplifying this gives:

\[ 2 + x - 8 = 0 \implies x - 6 = 0 \implies x = +6 \]

**Oxidation number of sulfur in \( H_2SO_4 \) = +6**

### Summary of Oxidation Numbers

- \( S_8 \): 0
- \( S_2F_2 \): +1
- \( H_2S \): -2
- \( H_2SO_4 \): +6

### Final Answer

The oxidation numbers of sulfur in \( S_8, S_2F_2, H_2S, \) and \( H_2SO_4 \) are respectively: **0, +1, -2, +6.**

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