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In the binomial expansion of (a-b)^n , n...

In the binomial expansion of `(a-b)^n , ngeq5,` the sum of 5th and 6th terms is zero, then `a/b` equals (1) `5/(n-4)` (2) `6/(n-5)` (3) `(n-5)/6` (4) `(n-4)/5`

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In the binomial expansion of (a - b)^n , n ge 5 the sum of the 5th and 6th term is zero , then find a/b

In the binomial expansion of (a-b)^n,ngeq5, the sum of the 5th and 6th term is zero. Then a//b equals (n-5)//6 b. (n-4)//5 c. n//(n-4) d. 6//(n-5)

Knowledge Check

  • In the binomial expansion of (a-b)^(n) , n ge 5 , the sum of 5th and 6th terms is zero, then (a)/(b) equals

    A
    (a) `(n-5)/(6)`
    B
    (b) `(n-4)/(5)`
    C
    (c) `(5)/(n-4)`
    D
    (d) `(6)/(n-5)`

  • If the sum of n terms of an A.P. is 2n^(2)+5n , then its n^(th) term

    A
    A. `4n-3`
    B
    B. `3n-4`
    C
    C. `4n+3`
    D
    D. `3n +9`

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