The point diametrically opposite to the point P (1, 0) on the circle `x^2+""y^2+""2x""+""4y-3""=""0` is (1) `(3,-4)` (2) `(-3,""4)` (3) `(-3,-4)` (4) `(3,""4)`

Explanation

To find the point diametrically opposite to the point \( P(1, 0) \) on the circle given by the equation \( x^2 + y^2 + 2x + 4y - 3 = 0 \), we can follow these steps:

### Step 1: Rewrite the circle equation in standard form
The general equation of a circle is given by:
\[ x^2 + y^2 + 2gx + 2fy + c = 0 \]
From the given equation \( x^2 + y^2 + 2x + 4y - 3 = 0 \), we can identify:
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