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A person of mass m is standing in a lift...

A person of mass m is standing in a lift. Find his apparent weight when the lift is : moving downward with uniform acceleration `a(lt g)`

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Knowledge Check

  • A person of mass 60 kg is in a lift. The change in the apparent weight of the person, when the lift moves up with an acceleration of 2ms^(-2) and then down with an acceleration of 2ms^(-2) is ("take g = "10 m//sec^(2))

    A
    120 N
    B
    240 N
    C
    480 N
    D
    720 N

  • The mass of man when standing on the lift is 60 kg. The weight when the lift is moving upwards with acceration 4.9 ms^(-2) is

    A
    882 N
    B
    600 N
    C
    306 N
    D
    zero

  • A man of mass 70 kg stands on a weighing scale in a lift which is moving downward with the uniform acceleration of 5 m/s^2 . The reading on the weighing scale is

    A
    70 kg
    B
    35 kg
    C
    105 kg
    D
    700 kg

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    A man of mass m is standing on the floor of a lift. Find his apparent weight when the lift is moving upwards with uniform acceleration a.

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    A man of mass m is standing on the floor of a lift. Find his apparent weight when the lift falling freely. Take acceleration due to gravity equal to g.

    A person of mass 50kg stands on a weighting scale on a lift If the lift is ascending upwards with a uniform acceleration of 9ms^(-2) what would be the reading of the weighing scale?(g=10ms^(-1)) in kg wt

    The person o( mass 50 kg slands on a weighing scale on a lift. If the lift is ascending upwards with a uniform acceleration of 9ms^(-2) , what would be the reading of the weighting scale? ("Take g"=10ms^(-2))

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