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The oxidation number of carbon in Glucos...

The oxidation number of carbon in Glucose is _______

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The correct Answer is:
0
Glucose = `C_(6)H_(12)O_6` consider the oxidation number of carbon as .x.
`C_(6)H_(12)O_(6):6(x)+12(1)+6(-2)=0`
`6x+12-12=0`
`:. X =0`
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