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A mosquito net over a 7 f t xx 4 f t bed...

A mosquito net over a `7 f t xx 4 f t` bed is 3 ft high. The net has a hole at one corner of the bed through which a mosquito entres the net
Taking the hols as origin, the length of the bed as the x-axis, it.s width as the y-axis and vertically up as the z-axis, write the components of the displacement vector

A

`sqrt54` ft

B

8ft

C

`sqrt74` ft

D

`sqrt64` ft

Text Solution

Verified by Experts

The correct Answer is:
C
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An electric field is uniform and in the positive x direction for positive x and uniform with the same magnitude but in the negative x direction for negative x. It is given that E=200 hat(i) N//C for x gt 0 and E=-200 hat(i) N//C for x lt 0 . A right circular cylinder of length 20 cm and radius 5 cm has its centre at the origin and its axis along the x-axis so that one face is at x=+10 cm and the other is at x=-10 cm What is the net outward flux through the xylinder?

Knowledge Check

  • A rectangular loop of wire is placed in the XY-plane with its side of length 3 cm parallel to the X-axis and the side of length 4 cm parallel to the Y-axis. It is moving in the positive X-direction with the speed 10 cm/s. A magnetic field exists in the space with its direction parallel to the Z-axis. The field decreases by 2xx10^(-3) T/cm along the positive X-axis and increases in time by 2 xx 10^(-2) T/s. The induced emf in the wire is

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    `-4.8 xx 10^(-5) V`
    B
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  • It is tempting to think that all possible transitions are permissible, and that an atomic spectrum arises from the transition of the electron from any initial orbital to any other orbital. However, this is not so, because a photon has an intrinsic spin angular momentum of sqrt2 (h)/(2pi) corresponding to S = 1 although it has no charge and no rest mass. On the other hand, an electron has got two types of angular momentum : Orbital angular momentum, L=sqrt(l(l+1))h/(2pi) and spin angular momentum, arising from orbital motion and spin motion of electron respectively. The change in angular momentum of the electron during any electronic transition must compensate for the angular momentum carries away by the photon. to satisfy this condition the difference between the azimuthal quantum numbers of the orbital within which transition takes place must differ by one. Thus, an electron in a d-orbital (1 = 2) cannot make a transition into an s = orbital (I = 0) because the photon cannot carry away enough angular momentum. An electron as is well known, possess four quantum numbers n, I, m and s. Out of these four I determines the magnitude of orbital angular momentum (mentioned above) while (2n m determines its z-components as m((h)/(2pi)) the permissible values of only integers right from -1 to + l. While those for I are also integers starting from 0 to (n − 1). The values of I denotes the sub shell. For I = 0, 1, 2, 3, 4,..... the sub-shells are denoted by the symbols s, p, d, f, g, .... respectively The orbital angular momentum of an electron in p-orbital makes an angle of 45^@ from Z-axis. Hence Z-component of orbital angular momentum of election is :

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    B
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    C
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  • Let A be a vertex of the ellipse S = (x^2)/(4) + (y^2)/(9) - 1 = 0 and F be focus of the ellipse S' = (x^2)/(9) + (y^2)/(4) - 1 = 0 .Let P be a point on the major axis of the ellipse S' = 0 , which divides bar(OF) in the ratio 2 : 1 (O is the origin ). If the length of the chord of the ellipse S = 0 through A and P is (3 sqrt101)/(k) , then k =

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