Calculate the ratio of electric and gravitational force between two protons. Charge of each proton is `1.6 xx 10^(-19)C`, mass is `1.672 xx 10^(-27)kg and G= 6.67 xx 10^(-11) Nm^(2) kg^(-2)`.

Explanation

`Q_(1) = 1.6 xx 10^(-19)C, Q_(2) = 1.6 xx 10^(-19)C`
r is the distance between the two protons
Electrostatic force between two protons `F_(1) = 9 xx 10^(9) (Q_(1)Q_(2))/(r^(2)), m_(1) = m_(2) = 1.672 xx 10^(-27) kg`
`G= 6.67 xx 10^(-11) Nm^(2)//kg^(2)`
Gravitational force between them `F_(2) = G(m_(1) m_(2))/(r^(2)) therefore (F_(1))/(F_(2)) = (9 xx 10^(9) Q_(1) Q_(2))/(G.m_(1)m_(2))= (9 xx 10^(9) xx 1.6 xx 10^(-19) xx 1.6 xx 10^(-19))/(6.67 xx 10^(-11) xx 1.672 xx 10^(-27) xx 1.672 xx 10^(-27)) = 1.23 xx 10^(36)`