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Two separate monochromatic light beams A...

Two separate monochromatic light beams A and B of the same intensity are falling normally on a unit area of a metallic surface. Their wave lengths are `lamda_(A)` and `lamda_(B)`, respectively. Assuming that all the incident light is used in ejecting the photoelectrons the ratio of the photoelectrons from the beam A to that from B is :

A

`(lamda_(A)//lamda_(B))^(2)`

B

`(lamda_(B)//lamda_(A))^(2)`

C

`(lamda_(A)//lamda_(B))`

D

`(lamda_(B)//lamda_(A))1`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • K_(1) and K_(2) are the maximum kinetic energies of the photo electrons emitted when light of wave lengths lamda_(1) , and lamda_(2) , respectively are incident on a metallic surface. If lamda_(1)=3lamda_(2) then

    A
    `K_(1)gt(K_(2))/(3)`
    B
    `K_(1)lt(K_(2))/(3)`
    C
    `K_(1)gt3K_(2)`
    D
    `K_(2)=3K_(1)`
  • Two satellite A and B revolve round the earth in circular orbits at heights R_(A) and R_(B) respectively from the surface of the earth. If the radius of the earth is R_(E) , the ratio of magnitude of the velocities fo the satellites is

    A
    `sqrt((R_(B) + R_(E))/(R_(A) + R_(E)))`
    B
    `(R_(B) + R_(E))/(R_(A) + R_(E))`
    C
    `sqrt((R_(B))/(R_(A)))`
    D
    `(R_(B))/(R_(A))`
  • Photoelectric emission is observed from a metallic surface for frequencies v_(1) and v_(2) of the incident light (v_(1)gtv_(2)) .If the maximum values of kinetic energy of the photoelectrons emitted in the two cases are in the ratio 1:n, then the threshold frequency of the metallic surface is

    A
    `(v_(1)-v_(2))/((n-1)`
    B
    `(nv_(1)-v_(2))/((n-1)`
    C
    `(nv_(2)-v_(1))/((n-1)`
    D
    `(v_(1)-v_(2))/((n-1)`
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