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(A) : Photoemission of electrons from a ...

(A) : Photoemission of electrons from a photosensitive surface is possible only if the incident radiation has a frequency above threshold frequency
(R): Unless the `hv > hv_(0)` = work function of metals, no photoemission of electrons is possible

A

A and R are true and R is the correct explanation of A.

B

A and R are true and R is not the correct explanation of A.

C

A is true, R is false.

D

A is false, R is true.

Text Solution

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The correct Answer is:
A
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Electrons are emitted with zero velocity from a metal surface when it is exposed to radiation of wavelength 6800 Å. Calculate threshold frequency (V_(0)) and work function (W_(0)) of metal.

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Knowledge Check

  • All electrons ejected from a metal surface by the incident light of wavelength 200 nm can be stopped before travelling 1 m in the direction of uniform electric field of 4NC^(-1) . The work function of the metal surface is

    A
    2 eV
    B
    2.2 eV
    C
    4 eV
    D
    6.2 eV
  • The energies of the incident photons are 3, 4, 5 eV. The work functions of the metals are 0.5, 1.5, 2.5 eV. The maximum K.E.s of the photo electrons are in the ratio

    A
    `3:4:5`
    B
    `1:3:5`
    C
    `1:1:1`
    D
    `5:3:1`
  • Which of the following equations does represent the velcity (v) of the ejected electrons when a metal is made to strike with light of frequency v and threshold frequency of the metal is v_(0) ? ( m_(e) = mass of electron and h is Plank's constant)

    A
    `v = sqrt((h(v-v_(0)))/(m_(e)))`
    B
    `v = sqrt((2h(v-v_(0)))/(m_(e)))`
    C
    `v = sqrt((h(v-v_(0)))/(2m_(e)))`
    D
    `v = sqrt(h (v - v_(0))m_(e))`
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    Electrons are emitted with zero velocity from a metal surface when it is exposed to radiation of wavelength 4000Å . What is the threshold frequency (upsilon_(0)) ?

    The work function of caesium metal is 2.14 eV . When light of frequency 6xx 10^(14) Hz is incident on the metal surface , photomission of electrons occurs . What is the stopping potential and

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