A constant force acting on a body of mass of 5 kg change its speed from `5ms^(-1) "to" 10ms^(-1)` in 10 s without changing the direction of motion. The force acting on the body is

Options

A. 1. 1.5N
B. 2. 2N
C. 3. 2.5N
D. 4. 5N

Explanation

To solve the problem, we need to find the force acting on a body of mass 5 kg that changes its speed from 5 m/s to 10 m/s in 10 seconds. We can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).

### Step-by-Step Solution:

1. **Identify the given values:**
- Mass (m) = 5 kg
- Initial velocity (u) = 5 m/s
- Final velocity (v) = 10 m/s
- Time (t) = 10 s

2. **Calculate the acceleration (a):**
- Acceleration is defined as the change in velocity over time.
- Formula:
\[ a = \frac{v - u}{t} \]
- Substituting the values:
\[ a = \frac{10 \, \text{m/s} - 5 \, \text{m/s}}{10 \, \text{s}} = \frac{5 \, \text{m/s}}{10 \, \text{s}} = 0.5 \, \text{m/s}^2 \]

3. **Calculate the force (F):**
- Using Newton's second law:
\[ F = m \cdot a \]
- Substituting the values:
\[ F = 5 \, \text{kg} \cdot 0.5 \, \text{m/s}^2 = 2.5 \, \text{N} \]

4. **Conclusion:**
- The force acting on the body is **2.5 N**.