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A positively charged particle is release...

A positively charged particle is released from rest in a uniform electric field. The electric potential energy of the charge.

A

remains a constant because the electric field is uniform.

B

increases because the charge moves along the electric field.

C

decreases because the charge moves along the electric field.

D

decreases because the charge moves opposite to the electric field.

Text Solution

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The correct Answer is:
To solve the problem regarding the electric potential energy of a positively charged particle released from rest in a uniform electric field, we can follow these steps: ### Step 1: Understand the Concept of Electric Field An electric field (E) is a region around a charged particle where other charged particles experience a force. The direction of the electric field is defined as the direction of the force that a positive charge would experience. **Hint:** Recall that the electric field points away from positive charges and towards negative charges. ### Step 2: Analyze the Movement of the Charged Particle When a positively charged particle is released from rest in a uniform electric field, it will experience a force in the direction of the electric field. This means that the particle will start to move in the direction of the electric field. **Hint:** Remember that a positively charged particle moves in the direction of the electric field lines. ### Step 3: Relate Electric Potential and Electric Field The relationship between electric potential (V) and electric field (E) is given by the equation: \[ E = -\frac{dV}{dx} \] This indicates that the electric field is related to the rate of change of electric potential with respect to position. **Hint:** Consider how potential changes as you move through the electric field. ### Step 4: Determine the Direction of Potential Change As the positively charged particle moves in the direction of the electric field, it moves from a region of higher electric potential to a region of lower electric potential. This means that the potential (V) decreases as the particle moves. **Hint:** Think about how potential energy is affected when moving from high to low potential. ### Step 5: Analyze the Change in Electric Potential Energy The electric potential energy (U) of a charge in an electric field is given by: \[ U = qV \] where \( q \) is the charge and \( V \) is the electric potential. Since the particle is moving to a region of lower potential, the electric potential energy of the charge decreases. **Hint:** Remember that potential energy decreases when moving to lower potential for a positive charge. ### Conclusion Thus, when a positively charged particle is released from rest in a uniform electric field, the electric potential energy of the charge decreases as it moves along the direction of the electric field. **Final Answer:** The electric potential energy of the charge decreases.

To solve the problem regarding the electric potential energy of a positively charged particle released from rest in a uniform electric field, we can follow these steps: ### Step 1: Understand the Concept of Electric Field An electric field (E) is a region around a charged particle where other charged particles experience a force. The direction of the electric field is defined as the direction of the force that a positive charge would experience. **Hint:** Recall that the electric field points away from positive charges and towards negative charges. ### Step 2: Analyze the Movement of the Charged Particle ...
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Knowledge Check

  • A proton is kept at rest. A positively charged particle is released from rest at a distance d in its field. Consider two experiments, one ini which the charged particle is also a proton and in another, a position. In the same time t , the work done on the two moving charged particles is

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    B
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    same as the work done by charged particle on the stationary proton.
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