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Biot-Savart law indicates that the movin...

Biot-Savart law indicates that the moving electrons (velocity `vecv` ) produce a magnetic field `vecB` such that

A

`vec(B) _|_vec(v)`

B

`vec(B) || vec(v)`

C

it obeys inverse cube law.

D

it is along the line joining the electron and point of observation.

Text Solution

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The correct Answer is:
To solve the question regarding the Biot-Savart law and the characteristics of the magnetic field produced by moving electrons, we can break it down step by step. ### Step-by-Step Solution: 1. **Understanding Biot-Savart Law**: The Biot-Savart law describes how moving charges produce a magnetic field. The law can be mathematically expressed as: \[ \vec{B} = \frac{\mu_0}{4\pi} \frac{q \vec{v} \times \vec{r}}{r^3} \] where: - \(\vec{B}\) is the magnetic field, - \(\mu_0\) is the permeability of free space, - \(q\) is the charge, - \(\vec{v}\) is the velocity of the charge, - \(\vec{r}\) is the position vector from the charge to the point of observation, - \(r\) is the magnitude of \(\vec{r}\). 2. **Direction of the Magnetic Field**: The direction of the magnetic field \(\vec{B}\) is given by the right-hand rule, which states that if you point your thumb in the direction of \(\vec{v}\) (the velocity of the charge) and curl your fingers towards \(\vec{r}\) (the position vector), your palm will point in the direction of \(\vec{B}\). This indicates that \(\vec{B}\) is perpendicular to both \(\vec{v}\) and \(\vec{r}\). 3. **Magnitude of the Magnetic Field**: The magnitude of the magnetic field can be simplified from the Biot-Savart law: \[ |\vec{B}| = \frac{\mu_0}{4\pi} \frac{q v \sin \theta}{r^2} \] where \(\theta\) is the angle between \(\vec{v}\) and \(\vec{r}\). This shows that the magnetic field strength is inversely proportional to the square of the distance \(r\) from the charge, not the cube. 4. **Evaluating the Options**: - **Option A**: \(\vec{B}\) is perpendicular to \(\vec{v}\) (Correct). - **Option B**: \(\vec{B}\) is parallel to \(\vec{v}\) (Incorrect). - **Option C**: It obeys inverse cube law (Incorrect; it obeys inverse square law). - **Option D**: It is along the line joining the electron and the point of observation (Incorrect). 5. **Conclusion**: The correct answer is that the magnetic field \(\vec{B}\) produced by moving electrons is perpendicular to the velocity \(\vec{v}\). ### Final Answer: The correct option is **A**: \(\vec{B}\) is perpendicular to \(\vec{v}\).

To solve the question regarding the Biot-Savart law and the characteristics of the magnetic field produced by moving electrons, we can break it down step by step. ### Step-by-Step Solution: 1. **Understanding Biot-Savart Law**: The Biot-Savart law describes how moving charges produce a magnetic field. The law can be mathematically expressed as: \[ \vec{B} = \frac{\mu_0}{4\pi} \frac{q \vec{v} \times \vec{r}}{r^3} \] ...
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Knowledge Check

  • If an electron is moving with velocity v produces a magnetic field vecB , then

    A
    the direction of field `vecB` will be same as the direction of velocity `vecv.`
    B
    the direction of field `vecB` will be opposite to the direction of velocity `vecv.`
    C
    the direction of field `vecB` will be perpendicular to the direction of velocity `vecv.`
    D
    the direction of field `vecB` does not depend upon the direction of velocity `vecv.`
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