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On heating a mixture of NH4 Cl and KNO2,...

On heating a mixture of `NH_4 Cl` and `KNO_2`, we get

A

`NH_(4)NO_(3)`

B

`KNH_(4)(NO_(3))_(2)`

C

`N_(2)`

D

`NO`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the reaction between a mixture of \( NH_4Cl \) and \( KNO_2 \) upon heating, we can follow these steps: ### Step 1: Identify the Reactants The reactants in this case are: - Ammonium chloride (\( NH_4Cl \)) - Potassium nitrite (\( KNO_2 \)) ### Step 2: Understand the Reaction When \( NH_4Cl \) is heated with \( KNO_2 \), a chemical reaction occurs. We need to determine the products of this reaction. ### Step 3: Write the Balanced Chemical Equation The balanced chemical equation for the reaction is: \[ NH_4Cl + KNO_2 \rightarrow N_2 + KCl + 2H_2O \] This indicates that nitrogen gas (\( N_2 \)), potassium chloride (\( KCl \)), and water (\( H_2O \)) are produced. ### Step 4: Analyze the Oxidation States - In \( NH_4Cl \), nitrogen has an oxidation state of -3. - In \( KNO_2 \), nitrogen has an oxidation state of +3. - In the product \( N_2 \), nitrogen has an oxidation state of 0. This shows that \( NH_4Cl \) acts as a reducing agent (it donates electrons), while \( KNO_2 \) acts as an oxidizing agent (it accepts electrons). ### Step 5: Identify the Main Product From the balanced equation, we can see that the main gaseous product formed is nitrogen gas (\( N_2 \)). ### Conclusion Thus, upon heating a mixture of \( NH_4Cl \) and \( KNO_2 \), the primary product obtained is nitrogen gas (\( N_2 \)). ### Final Answer The correct answer is \( N_2 \). ---
To solve the question regarding the reaction between a mixture of \( NH_4Cl \) and \( KNO_2 \) upon heating, we can follow these steps: ### Step 1: Identify the Reactants The reactants in this case are: - Ammonium chloride (\( NH_4Cl \)) - Potassium nitrite (\( KNO_2 \)) ### Step 2: Understand the Reaction ...
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