Which of the following compounds has the highest boiling point?

Options

A. `CH_3CH_2CH_2Cl`
B. `CH_3CH_2CH_2CH_2Cl`
C. `CH_3CH(CH_3)CH_2Cl`
D. `(CH_3)_3C Cl`

Explanation

To determine which compound has the highest boiling point among the given options, we need to analyze the factors that influence boiling points, particularly focusing on molecular mass, surface area, and branching.

### Step-by-Step Solution:

1. **Understanding Boiling Points**:
- Boiling points of compounds are influenced by the strength of intermolecular forces. The stronger the forces, the higher the boiling point.

2. **Types of Intermolecular Forces**:
- The primary forces at play for haloalkanes and haloarenes are Van der Waals forces (dispersion forces), which depend on molecular mass and surface area.

3. **Molecular Mass**:
- Generally, higher molecular mass leads to stronger Van der Waals forces due to increased electron cloud size, which enhances polarizability.

4. **Surface Area**:
- A larger surface area allows for more contact between molecules, increasing the strength of Van der Waals forces. This is typically greater in straight-chain (unbranched) compounds compared to branched ones.

5. **Analyzing the Options**:
- Let's denote the options as A, B, C, and D, where:
- Option A has 3 carbons
- Options B, C, and D have 4 carbons each.
- Since option A has fewer carbons, it will have a lower molecular mass and consequently weaker Van der Waals forces.

6. **Branching**:
- Among the options with 4 carbons, we need to check for branching. Less branching means a larger surface area.
- If one of the options (say B) is straight-chain (unbranched), while the others (C and D) are branched, option B will have the highest boiling point due to its higher surface area and stronger Van der Waals forces.

7. **Conclusion**:
- Based on the analysis, the compound with the highest boiling point is the one with the highest molecular mass and the least branching. Therefore, if option B is unbranched, it will have the highest boiling point.

### Final Answer:
The compound with the highest boiling point is **Option B** (assuming it is the unbranched one with 4 carbons).