What will be the products of electrolysis of `AgNO_(3)` solution in water with platinum electrodes ?

Options

A. Ag is liberated at cathode and Ag is deposited in anode.
B. Ag is liberated at cathode and `O_(2)` is liberated at anode.
C. Ag is liberated at anode and water is liberated at cathode.
D. Ag is liberated at cathode and silver oxide is liberated at anode.

Explanation

To determine the products of the electrolysis of an AgNO3 solution in water with platinum electrodes, we can follow these steps:

### Step 1: Dissociation of AgNO3
The first step in the electrolysis process is the dissociation of silver nitrate (AgNO3) in water. This dissociation produces silver ions (Ag⁺) and nitrate ions (NO₃⁻).

**Equation:**
\[ \text{AgNO}_3 \rightarrow \text{Ag}^+ + \text{NO}_3^- \]

### Step 2: Ionization of Water
Water also undergoes self-ionization, producing hydrogen ions (H⁺) and hydroxide ions (OH⁻).

**Equation:**
\[ \text{H}_2\text{O} \rightarrow \text{H}^+ + \text{OH}^- \]

### Step 3: Reactions at the Electrodes
In electrolysis, reactions occur at both the cathode (negative electrode) and the anode (positive electrode).

#### At the Cathode:
At the cathode, the silver ions (Ag⁺) will gain electrons (reduction) to form solid silver (Ag).

**Equation:**
\[ \text{Ag}^+ + e^- \rightarrow \text{Ag} \]

#### At the Anode:
At the anode, water will undergo oxidation, producing oxygen gas (O₂), hydrogen ions (H⁺), and electrons.

**Equation:**
\[ 2\text{H}_2\text{O} \rightarrow 4\text{H}^+ + \text{O}_2 + 4e^- \]

### Step 4: Summary of Products
From the reactions at the electrodes, we can summarize the products of the electrolysis:
- At the cathode, solid silver (Ag) is deposited.
- At the anode, oxygen gas (O₂) is liberated.

### Final Answer:
The products of the electrolysis of AgNO3 solution in water with platinum electrodes are:
- **At the Cathode:** Silver (Ag)
- **At the Anode:** Oxygen gas (O₂)