Resistivity of 0.5 M electrolytic solution is `10Omega`cm, then find out the molar conductivity of solution.

Explanation

`Lamda_(m)=`molar conductivity of solution
`kappa`=specific conductivity of solution
p=resistivity of solution=`10Omegacm=0.1Omegacm`
`kappa=(1)/(p)=(1)/(10)=0.1Omega^(-1)cm^(-1)=0.1" S "cm^(-1)`
Concentration of solution :
`c=0.5" mol "L^(-1)=0.5" mol "cm^(-3)`
`=1000xx0.5" mol "m^(-3)`
`=500.0" mol "m^(-3)`
`Lamda_(m)=(1000kappa)/(c)=(1000xx0.1" S "cm^(-1))/(0.05" mol "cm^(-3))`
`=200" S "cm^(3)mol^(-1)`