How would you determine the standard ele...

How would you determine the standard electrode potential of the system `Mg^(2+) | Mg` ?

Text Solution

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* The standard electrode potential of `Mg^(2+)|Mg` can be measured with respect to the standard hydrogen electrode, represented by `Pt_((S)),H_(2(g))(1atm)|H_((aq))^(+)(1M)`.
* A cell, consisting of `Mg|MgSO_(4(aq))1M` as the anode and the standard hydrogen electrode as the cathode is set up.
`Mg|Mg_((aq))^(2+)(1M)||H_((aq))^(+)(1M)|H_(2(g))(1" bar")|Pt_((S))`
* Then, the emf of the cell is measured and this measured emf is the standard hydrogen electrode as the cathode is set up.
`Mg|Mg_((aq))^(2+)(1M)||H_((aq))^(+)(1M)|H_(2(g))(1" bar")|Pt_((S))`
* Then, the emf of the cell is measured and this measured emf is the standard electrode potential of the magnesium electrode.
`E^(Theta)=E_(R)^(Theta)-E_(L)^(Theta)`
* Here, `E^(Theta)` for the standard hydrogen electrode is zero.
Therefore, `E^(Theta)=0-E_(L=E_(L)^(Theta))^(Theta)`

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Which cell will measure standard electrode potential of copper electrode ?

`Pt_((S))|H_(2(g,0.1" bar"))|H_((aq,1M))^(+)||Cu_((aq,1M))^(2+)|Cu`

`Pt_((S))|H_(2(g,1" bar"))|H_((aq,1M))^(+)||Cu_((aq,2M))^(2+)|Cu`

`Pt_((S))|H_(2(g,1" bar"))|H_((aq,0.1M))^(+)||Cu_((aq,1M))^(2+)|Cu`

`Pt_((S))|H_(2(g,1" bar"))|H_((aq,1M))^(+)||Cu_((aq,1M))^(2+)|Cu`

Metallic elements are described by their standard electrode potential, fusion enthalpy, atomic size, etc. The alkali metals are characterised by which of the following properties?

High boiling point

High negative standard electrode potential

High density

Large atomic size

Which is increasing order of the reducing power of the following metals on the basis of standard electrode potential ? Ag^(+)//Ag=0.80 V " "Mg^(2+)//Mg=-2.37V Hg^(2+)//Hg=0.79V" "Cr^(3+)//Cr=-0.74V

`Hg lt Ag lt Mg lt Cr`

`Cr lt Mg lt Ag lt Hg`

`Mg lt Cr lt Hg lt Ag`

`Ag lt Hg lt Cr lt Mg`